Optimal. Leaf size=939 \[ -\frac {b^2 e^2 m \log ^2(x) n^2}{2 d^2}+\frac {b^2 e^2 m \log ^2(d+e x) n^2}{4 d^2}-\frac {b^2 e^2 m \log \left (-\frac {e x}{d}\right ) \log ^2(d+e x) n^2}{2 d^2}+\frac {b^2 e^2 \log \left (f x^m\right ) \log ^2(d+e x) n^2}{2 d^2}-\frac {b^2 \log \left (f x^m\right ) \log ^2(d+e x) n^2}{2 x^2}-\frac {b^2 m \log ^2(d+e x) n^2}{4 x^2}+\frac {b^2 e^2 m \log (x) n^2}{d^2}+\frac {b^2 e^2 m \log \left (-\frac {e x}{d}\right ) n^2}{2 d^2}+\frac {b^2 e^2 \log (x) \log \left (f x^m\right ) n^2}{d^2}+\frac {b^2 e^2 m \log ^2(x) \log (d+e x) n^2}{2 d^2}-\frac {3 b^2 e^2 m \log (d+e x) n^2}{2 d^2}+\frac {b^2 e^2 m \log (x) \log (d+e x) n^2}{d^2}-\frac {b^2 e^2 m \log \left (-\frac {e x}{d}\right ) \log (d+e x) n^2}{2 d^2}-\frac {b^2 e^2 \log \left (f x^m\right ) \log (d+e x) n^2}{d^2}-\frac {b^2 e^2 \log (x) \log \left (f x^m\right ) \log (d+e x) n^2}{d^2}-\frac {b^2 e \log \left (f x^m\right ) \log (d+e x) n^2}{d x}-\frac {3 b^2 e m \log (d+e x) n^2}{2 d x}-\frac {b^2 e^2 m \log ^2(x) \log \left (\frac {e x}{d}+1\right ) n^2}{2 d^2}-\frac {b^2 e^2 m \log (x) \log \left (\frac {e x}{d}+1\right ) n^2}{d^2}+\frac {b^2 e^2 \log (x) \log \left (f x^m\right ) \log \left (\frac {e x}{d}+1\right ) n^2}{d^2}-\frac {b^2 e^2 \left (m-\log \left (f x^m\right )\right ) \text {Li}_2\left (-\frac {e x}{d}\right ) n^2}{d^2}-\frac {b^2 e^2 m (2 \log (d+e x)+1) \text {Li}_2\left (\frac {e x}{d}+1\right ) n^2}{2 d^2}-\frac {b^2 e^2 m \text {Li}_3\left (-\frac {e x}{d}\right ) n^2}{d^2}+\frac {b^2 e^2 m \text {Li}_3\left (\frac {e x}{d}+1\right ) n^2}{d^2}+\frac {b \left (m \log (x)-\log \left (f x^m\right )\right ) \left (e^2 \log \left (-\frac {e x}{d}\right ) x^2+(d+e x) (e x+(d-e x) \log (d+e x))\right ) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right ) n}{d^2 x^2}-\frac {b m \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right ) \left (2 \log (x) \log (d+e x) d^2+e x (d+e x)+e^2 x^2 \log \left (-\frac {e x}{d}\right )+\left (d^2-e^2 x^2\right ) \log (d+e x)+e x \left (e x \log ^2(x)+2 d (\log (x)+1)-2 e x \left (\log (x) \log \left (\frac {e x}{d}+1\right )+\text {Li}_2\left (-\frac {e x}{d}\right )\right )\right )\right ) n}{2 d^2 x^2}-\frac {m \log (x) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2}{2 x^2}-\frac {\left (-2 \log (x) m+m+2 \log \left (f x^m\right )\right ) \left (a-b n \log (d+e x)+b \log \left (c (d+e x)^n\right )\right )^2}{4 x^2} \]
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Rubi [F] time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{x^3} \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin {align*} \int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{x^3} \, dx &=\int \frac {\log \left (f x^m\right ) \left (a+b \log \left (c (d+e x)^n\right )\right )^2}{x^3} \, dx\\ \end {align*}
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Mathematica [A] time = 1.01, size = 781, normalized size = 0.83 \[ \frac {-2 b m n \left (\left (d^2-e^2 x^2\right ) \log (d+e x)+2 d^2 \log (x) \log (d+e x)+e^2 x^2 \log \left (-\frac {e x}{d}\right )+e x \left (-2 e x \left (\text {Li}_2\left (-\frac {e x}{d}\right )+\log (x) \log \left (\frac {e x}{d}+1\right )\right )+2 d (\log (x)+1)+e x \log ^2(x)\right )+e x (d+e x)\right ) \left (a+b \log \left (c (d+e x)^n\right )-b n \log (d+e x)\right )+d^2 \left (-2 \log \left (f x^m\right )+2 m \log (x)-m\right ) \left (a+b \log \left (c (d+e x)^n\right )-b n \log (d+e x)\right )^2-2 d^2 m \log (x) \left (a+b \log \left (c (d+e x)^n\right )-b n \log (d+e x)\right )^2+4 b n \left (e^2 x^2 \log \left (-\frac {e x}{d}\right )+(d+e x) ((d-e x) \log (d+e x)+e x)\right ) \left (m \log (x)-\log \left (f x^m\right )\right ) \left (a+b \log \left (c (d+e x)^n\right )-b n \log (d+e x)\right )+b^2 n^2 \left (-2 d^2 \log ^2(d+e x) \log \left (f x^m\right )-d^2 m \log ^2(d+e x)-2 e^2 x^2 \text {Li}_2\left (\frac {e x}{d}+1\right ) \left (2 m \log (d+e x)+2 \log \left (f x^m\right )-2 m \log (x)+m\right )+2 e^2 x^2 \log ^2(d+e x) \log \left (f x^m\right )-4 e^2 x^2 \log (d+e x) \log \left (f x^m\right )-4 e^2 x^2 \log \left (-\frac {e x}{d}\right ) \log (d+e x) \log \left (f x^m\right )-4 e^2 m x^2 \text {Li}_3\left (-\frac {e x}{d}\right )+4 e^2 m x^2 \text {Li}_3\left (\frac {e x}{d}+1\right )+4 e^2 m x^2 (\log (x)-1) \text {Li}_2\left (-\frac {e x}{d}\right )+e^2 m x^2 \log ^2(d+e x)-2 e^2 m x^2 \log \left (-\frac {e x}{d}\right ) \log ^2(d+e x)-2 e^2 m x^2 \log ^2(x) \log (d+e x)+2 e^2 m x^2 \log ^2(x) \log \left (\frac {e x}{d}+1\right )+2 e^2 m x^2 \log \left (-\frac {e x}{d}\right )-6 e^2 m x^2 \log (d+e x)+4 e^2 m x^2 \log (x) \log (d+e x)-2 e^2 m x^2 \log \left (-\frac {e x}{d}\right ) \log (d+e x)+4 e^2 m x^2 \log (x) \log \left (-\frac {e x}{d}\right ) \log (d+e x)-4 e^2 m x^2 \log (x) \log \left (\frac {e x}{d}+1\right )-4 d e x \log (d+e x) \log \left (f x^m\right )-6 d e m x \log (d+e x)+4 e^2 x^2 \log (x) \log \left (f x^m\right )-2 e^2 m x^2 \log ^2(x)+4 e^2 m x^2 \log (x)\right )}{4 d^2 x^2} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.49, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b^{2} \log \left ({\left (e x + d\right )}^{n} c\right )^{2} \log \left (f x^{m}\right ) + 2 \, a b \log \left ({\left (e x + d\right )}^{n} c\right ) \log \left (f x^{m}\right ) + a^{2} \log \left (f x^{m}\right )}{x^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{2} \log \left (f x^{m}\right )}{x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.88, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \ln \left (c \left (e x +d \right )^{n}\right )+a \right )^{2} \ln \left (f \,x^{m}\right )}{x^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {{\left (b^{2} {\left (m + 2 \, \log \relax (f)\right )} + 2 \, b^{2} \log \left (x^{m}\right )\right )} \log \left ({\left (e x + d\right )}^{n}\right )^{2}}{4 \, x^{2}} + \int \frac {2 \, b^{2} d \log \relax (c)^{2} \log \relax (f) + 4 \, a b d \log \relax (c) \log \relax (f) + 2 \, a^{2} d \log \relax (f) + 2 \, {\left (b^{2} e \log \relax (c)^{2} \log \relax (f) + 2 \, a b e \log \relax (c) \log \relax (f) + a^{2} e \log \relax (f)\right )} x + {\left (4 \, b^{2} d \log \relax (c) \log \relax (f) + 4 \, a b d \log \relax (f) + {\left (4 \, a b e \log \relax (f) + {\left (4 \, e \log \relax (c) \log \relax (f) + {\left (m n + 2 \, n \log \relax (f)\right )} e\right )} b^{2}\right )} x + 2 \, {\left (2 \, b^{2} d \log \relax (c) + 2 \, a b d + {\left ({\left (e n + 2 \, e \log \relax (c)\right )} b^{2} + 2 \, a b e\right )} x\right )} \log \left (x^{m}\right )\right )} \log \left ({\left (e x + d\right )}^{n}\right ) + 2 \, {\left (b^{2} d \log \relax (c)^{2} + 2 \, a b d \log \relax (c) + a^{2} d + {\left (b^{2} e \log \relax (c)^{2} + 2 \, a b e \log \relax (c) + a^{2} e\right )} x\right )} \log \left (x^{m}\right )}{2 \, {\left (e x^{4} + d x^{3}\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\ln \left (f\,x^m\right )\,{\left (a+b\,\ln \left (c\,{\left (d+e\,x\right )}^n\right )\right )}^2}{x^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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